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प्रश्न
Solve the following quadratic equation:
`(x + 3)/(x - 2) - (1 - x)/x = 4 1/4, x ≠ 2, 0`
योग
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उत्तर
`((x + 3))/((x - 2)) - ((1 - x))/x = 17/4`
⇒ `(x(x + 3) - (1 - x)(x - 2))/((x - 2)x) = 17/4`
⇒ `(x^2 + 3x - (x - 2 - x^2 + 2x))/(x^2 - 2x) = 17/4`
⇒ `(x^2 + 3x + x^2 - 3x + 2)/(x^2 - 2x) = 17/4`
⇒ `(2x^2 + 2)/(x^2 - 2x) = 17/4`
⇒ 8x2 + 8 = 17x2 – 34x ...(Cross multiplication)
⇒ –9x2 + 34x + 8 = 0
⇒ 9x2 – 34x – 8 = 0
⇒ 9x2 – 36x + 2x – 8 = 0
⇒ 9x(x – 4) + 2(x – 4) = 0
⇒ (x – 4) (9x + 2) = 0
⇒ x – 4 = 0 or 9x + 2 = 0
⇒ `x = 4` or `x = (-2)/9`
Hence, the roots of the equation are 4 and `(-2)/9`.
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