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प्रश्न
Solve the following quadratic equation:
9x2 – 3x – 2 = 0
योग
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उत्तर
We write, –3x = 3x – 6x as 9x2 × (–2) = –18x2 = 3x × (–6x)
∴ 9x2 – 3x – 2 = 0
⇒ 9x2 + 3x – 6x – 2 = 0
⇒ 3x(3x + 1) – 2(3x + 1) = 0
⇒ (3x + 1)(3x – 2) = 0
⇒ 3x + 1 = 0 or 3x – 2 = 0
⇒ `x = -1/3` or `x = 2/3`
Hence, the roots of the given equation are `-1/3` and `2/3`.
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