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प्रश्न
Solve the following quadratic equation:
48x2 – 13x – 1 = 0
योग
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उत्तर
Given:
48x2 – 13x – 1 = 0
⇒ 48x2 – (16x – 3x) – 1 = 0
⇒ 48x2 – 16x + 3x – 1 = 0
⇒ 16x(3x – 1) + 1(3x – 1) = 0
⇒ (16x + 1)(3x – 1) = 0
⇒ 16x + 1 = 0 or 3x – 1 = 0
⇒ `x = (-1)/16` or `x = 1/3`
Hence, the roots of the equation are `(-1)/16` and `1/3`.
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