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प्रश्न
Solve the following quadratic equation:
`3sqrt(7)x^2 + 4x - sqrt(7) = 0`
योग
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उत्तर
Given:
`3sqrt(7)x^2 + 4x - sqrt(7) = 0`
⇒ `3sqrt(7)x^2 + 7x - 3x - sqrt(7) = 0`
⇒ `sqrt(7)x(3x + sqrt(7)) - 1(3x + sqrt(7)) = 0`
⇒ `(3x + sqrt(7)) (sqrt(7) - 1) = 0`
⇒ `3x + sqrt(7) = 0` or `sqrt(7)x - 1 = 0`
⇒ `x = (-sqrt(7))/3` or `x = 1/sqrt(7) = (1 xx sqrt(7))/(sqrt(7) xx sqrt(7)) = sqrt(7)/7`
Hence, the roots of the equation are `(-sqrt(7))/3` and `sqrt(7)/7`.
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