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Solve the following quadratic equation: 1/(x – 1) – 1/(x + 5) = 6/7, x ≠ 1, –5

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प्रश्न

Solve the following quadratic equation:

`1/(x - 1) - 1/(x + 5) = 6/7, x ≠ 1, -5`

योग
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उत्तर

`1/(x - 1) - 1/(x + 5) = 6/7, x ≠ 1, -5`  

⇒ `(x + 5 - x + 1)/((x - 1)(x + 5)) = 6/7` 

⇒ `6/(x^2 + 4x - 5) = 6/7` 

⇒ x2 + 4x – 5 = 7 

⇒ x2 + 4x – 12 = 0 

⇒ x2 + 6x – 2x – 12 = 0 

⇒ x(x + 6) – 2(x + 6) = 0 

⇒ (x + 6)(x – 2) = 0 

⇒ x + 6 = 0 or x – 2 = 0

⇒ x = –6 or x = 2 

Hence, –6 and 2 are the roots of the given equation.  

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अध्याय 4: Quadratic Equations - EXERCISE 4A [पृष्ठ १८४]

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 4 Quadratic Equations
EXERCISE 4A | Q 55. (i) | पृष्ठ १८४
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