Question

Solve the following problem:

Following is the probability distribution of a r.v.X.

X	– 3	– 2	–1	0	1	2	3
P(X = x)	0.05	0.1	0.15	0.20	0.25	0.15	0.1

Find the probability that X is odd.

Answer 1

P(X is odd)

= P(X = –3 or X = –1 or X = 1 or X = 3)

= P(X = –3) + P(X = – 1) + P(X = 1) + P(X = 3)

= 0.05 + 0.15 + 0.25 + 0.10

= 0.55