Advertisements
Advertisements
प्रश्न
Solve the following pair of linear (simultaneous) equation by the method of elimination by substitution:
0.2x + 0.1y = 25
2(x - 2) - 1.6y = 116
Advertisements
उत्तर
The given pair of linear equations are
0.2x + 0.1y = 25 ...(1)
2(x - 2) - 1.6y = 116 ...(2)
Consider equation (1)
0.2x + 0.1y = 25
⇒ `(0.2x)/10+(0.1y)/10=25`
⇒ `(2x+y)/10=25`
⇒ 2x + y = 250
⇒ y = 250 - 2x ...(3)
Putting the value of y in equation (2)
⇒ 2(x - 2) - 1.6(250 - 2x) = 116
⇒ 2x - 4 - 400 + 3.2x = 116
⇒ 5.2x - 404 = 116
⇒ 5.2x = 116 + 404
⇒ 5.2x = 520
⇒ x = `520/5.2`
⇒ x = 100
From equation in (3)
`0.2/10(100) + 0.1y = 25`
`20+y/10=25`
`y/10=25-20`
`y/10=5`
y = 50
APPEARS IN
संबंधित प्रश्न
Solve the following pair of linear (simultaneous) equation by the method of elimination by substitution:
1.5x + 0.1y = 6.2
3x - 0.4y = 11.2
Solve the following pair of linear (simultaneous) equation using method of elimination by substitution:
3x + 2y =11
2x - 3y + 10 = 0
Solve th following pair of linear (Simultaneous ) equation using method of elimination by substitution :
`[ 2x + 1]/7 + [5y - 3]/3 = 12`
`[3x + 2 ]/2 - [4y + 3]/9 = 13`
Solve the following pair of linear (simultaneous) equation using method of elimination by substitution:
`[3x]/2 - [5y]/3 + 2 = 0`
`x/3 + y/2 = 2 1/6`
Solve the following pairs of linear (simultaneous) equation using method of elimination by substitution:
`x/6 + y/15 = 4`
`x/3 - y/12 = 4 3/4`
Solve the following simultaneous equations by the substitution method:
2x + 3y = 31
5x - 4 = 3y
Solve the following simultaneous equations by the substitution method:
13 + 2y = 9x
3y = 7x
Solve the following simultaneous equations by the substitution method:
0.4x + 0.3y = 1.7
0.7x - 0.2y = 0.8
Solve the following simultaneous equations by the substitution method:
3 - (x + 5) = y + 2
2(x + y) = 10 + 2y
Solve the following pairs of equations:
`(6)/(x + y) = (7)/(x - y) + 3`
`(1)/(2(x + y)) = (1)/(3( x - y)`
Where x + y ≠ 0 and x - y ≠ 0
The difference of two numbers is 3, and the sum of three times the larger one and twice the smaller one is 19. Find the two numbers.
The sum of four times the first number and three times the second number is 15. The difference of three times the first number and twice the second number is 7. Find the numbers.
A father's age is three times the age of his child. After 12 years, twice the age of father will be 36 more than thrice the age of his child. Find his present age.
* Question modified
Samidha and Shreya have pocket money Rs.x and Rs.y respectively at the beginning of a week. They both spend money throughout the week. At the end of the week, Samidha spends Rs.500 and is left with as much money as Shreya had in the beginning of the week. Shreya spends Rs.500 and is left with `(3)/(5)` of what Samidha had in the beginning of the week. Find their pocket money.
Solve by the method of elimination
x – y = 5, 3x + 2y = 25
Solve by the method of elimination
3(2x + y) = 7xy, 3(x + 3y) = 11xy
Solve by the method of elimination
`4/x + 5y` = 7, `3/x + 4y` = 5
Five years ago, a man was seven times as old as his son, while five year hence, the man will be four times as old as his son. Find their present age
