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Solve the following Linear Programming Problems graphically: Maximise Z = 3x + 4y subject to the constraints : x + y ≤ 4, x ≥ 0, y ≥ 0.

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प्रश्न

Solve the following Linear Programming Problems graphically:

Maximise Z = 3x + 4y

subject to the constraints : x + y ≤ 4, x ≥ 0, y ≥ 0.

योग
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उत्तर

The system of constraints is

x + y ≤ 4              ...(1)

and x ≥ 0,  y ≥ 0          ...(2)

Let l : x + y = 4 

The shaded region in the figure is the feasible region determined by the system of constraints (1) and (2).

It is observed that the feasible region OAB is bounded.

Thus, we use the Corner Point Method to determine the maximum value of Z.

We have Z = 3x + 4y                ...(3)

The coordinates of O, A and B are (0, 0), (4, 0) and (0, 4), respectively.

Corner Point Corresponding values of Z
(0, 0) 0
(4, 0) 12
(0, 4) 16 (Maximum)

Hence Zmax = 16 at the point (0, 4).

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अध्याय 12: Linear Programming - Exercise 12.1 [पृष्ठ ५१३]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 12 Linear Programming
Exercise 12.1 | Q 1 | पृष्ठ ५१३

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