Advertisements
Advertisements
प्रश्न
Solve the following inequation and represent the solution on the number line in following case:
3x + 2 ≥ 8, 2x + 1 ≤ 12
योग
Advertisements
उत्तर
3x + 2 ≥ 8
2x + 1 ≤ 12
Inequality 1:
3x + 2 ≥ 8
⇒ 3x ≥ 6
⇒ x ≥ 2
Inequality 2:
2x + 1 ≤ 12
⇒ 2x ≤ 11
⇒ x ≤ `11/2`
Combine the results:
2 ≤ x ≤ `11/2`
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
