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प्रश्न
Solve the following :
Find the area of the region bounded by the following curve, the X-axis and the given lines : y = sin x, x = 0, x = `pi/(3)`
योग
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उत्तर
Required area = `int_0^(pi/3)y*dx, "where" y = sin x`
= `int_0^(pi/3) sinx*dx`
= `[ - cos x]_0^(pi/3)`
= `- cos pi/(3) + cos 0`
= `-(1)/(2) + 1`
= `(1)/(2)"sq unit"`.
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