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प्रश्न
Solve the following equation using the formula:
x2 – 6x = 27
योग
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उत्तर
x2 – 6x = 27
`=>` x2 – 6x – 27 = 0
Here a = 1, b = – 6 and c = – 27
Then `x = (-b +- sqrt(b^2 - 4ac))/(2a)`
= `(-(-6) +- sqrt((-6)^2 - 4(1)(-27)))/(2(1))`
= `(6 +- 12)/2`
= `(6 +12)/2` and `(6 - 12)/2`
= 9 and –3
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