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प्रश्न
Solve the following equation by using formula:
`x - (1)/x = 3, x ≠ 0`
योग
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उत्तर
`x - (1)/x = 3`
x2 – 1 = 3x
⇒ x2 – 3x – 1 = 0
Here a = 1, b = -3, c = -1
∴ b2 - 4ac
= (-3)2 - 4 × 1 × (-1)
= 9 + 4
= 13
x = `(-b ± sqrt(b^2 - 4ac))/(2a)`
= `(-(-3) ± sqrt(13))/(2 xx 1)`
= `(3 ± sqrt(13))/(2)`
∴ x = `(3 + sqrt(13))/(2) and (3 - sqrt(13))/(2)`.
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