Advertisements
Advertisements
प्रश्न
Solve the following equation by factorization
`x^2 - (1 + sqrt(2))x + sqrt(2)` = 0
Advertisements
उत्तर
`x^2 - (1 + sqrt(2))x + sqrt(2)` = 0
⇒ `x^2 - x - sqrt(2)x + sqrt(2)` = 0
⇒ `(x - 1) - sqrt(2) (x - 1)`= 0
⇒ `(x - 1) (x - sqrt(2))` = 0
Either x - 1 = 0,
then x = 1
or
`x - sqrt(2)` = 0,
then x = `sqrt(2)`
Hence x = 1, `sqrt(2)`.
APPEARS IN
संबंधित प्रश्न
Solve for x : `(x+1)/(x-1)+(x-1)/(x+2)=4-(2x+3)/(x-2);x!=1,-2,2`
Solve the following quadratic equation by factorisation.
2y2 + 27y + 13 = 0
Solve the following quadratic equation by factorisation.
25m2 = 9
Solve the following quadratic equations by factorization:\[\frac{1}{x - 3} + \frac{2}{x - 2} = \frac{8}{x}; x \neq 0, 2, 3\]
If x = 1 is a common roots of the equations ax2 + ax + 3 = 0 and x2 + x + b = 0, then ab =
Solve the following equation: `("x" + 3)/("x" + 2) = (3"x" - 7)/(2"x" - 3)`
The side (in cm) of a triangle containing the right angle are 5x and 3x – 1. If the area of the triangle is 60 cm². Find the sides of the triangle.
In each of the following determine whether the given values are solutions of the equation or not.
x2 + 6x + 5 = 0; x = -1, x = -5
In each of the following determine whether the given values are solutions of the equation or not.
9x2 - 3x - 2 = 0; x = `-(1)/(3), x = (2)/(3)`
Solve the following equation by factorization
5x2 – 8x – 4 = 0 when x∈Q
