Advertisements
Advertisements
प्रश्न
Solve the following equation by factorization
`x + (1)/x = 2(1)/(20)`
Advertisements
उत्तर
`x + (1)/x = 2(1)/(20)`
⇒ 20x2 + 20 = 41x
⇒ 20x2 - 41x + 20 = 0
⇒ 20x2 - 16x - 25x + 20 = 0
⇒ 4x(5x - 4) -5(5x - 4) = 0
⇒ (5x - 4) (4x - 5) = 0
Either 5x - 4 = 0,
then 5x = 4
⇒ x = `(4)/(5)`
or
4x - 5 = 0,
then 4x = 5
⇒ x = `(5)/(4)`
Hence x = `(4)/(5), (5)/(4)`.
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equations
(i) x2 + 5x = 0 (ii) x2 = 3x (iii) x2 = 4
Find the roots of the following quadratic equation by factorisation:
2x2 + x – 6 = 0
Solve the following quadratic equations by factorization:
`1/(x+4)-1/(x-7)=11/30` , x ≠ 4, 7
A piece of cloth costs Rs. 35. If the piece were 4 m longer and each meter costs Rs. 1 less, the cost would remain unchanged. How long is the piece?
The sum of two natural numbers is 20 while their difference is 4. Find the numbers.
Solve the following quadratic equations by factorization:
\[\frac{4}{x} - 3 = \frac{5}{2x + 3}, x \neq 0, - \frac{3}{2}\]
Solve the following quadratic equations by factorization: \[\sqrt{3} x^2 - 2\sqrt{2}x - 2\sqrt{3} = 0\]
Find the value of k for which the following equations have real and equal roots:
\[x^2 - 2\left( k + 1 \right)x + k^2 = 0\]
Solve (x2 + 3x)2 - (x2 + 3x) -6 = 0.
Which of the following is correct for the equation `1/(x - 3) - 1/(x + 5) = 1`?
