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प्रश्न
Solve the following equation by factorization:
`sqrt(3)x^2 + 11x + 6sqrt(3) = 0`
योग
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उत्तर
Given,
⇒ `sqrt(3)x^2 + 11x + 6sqrt(3) = 0`
⇒ `sqrt(3)x^2 + 9x + 2x + 6sqrt(3) = 0`
⇒ `sqrt(3)x(x + 3sqrt(3)) + 2(x + 3sqrt(3)) = 0`
⇒ `(sqrt(3)x + 2)(x + 3sqrt(3)) = 0`
⇒ `(sqrt(3)x + 2) = 0` or `(x + 3sqrt(3)) = 0` ...[Using zero-product rule]
⇒ `sqrt(3)x = -2` or `x = -3sqrt(3)`
⇒ `x = (-2)/sqrt(3)` or `x = -3sqrt(3)`
Hence, `x = {(-2)/sqrt(3), -3sqrt(3)}`.
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