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प्रश्न
Solve the following equation by factorization
a2x2 + (a2+ b2)x + b2 = 0, a ≠ 0
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उत्तर
a2x2 + (a2+ b2)x + b2 = 0
⇒ a2x(x + 1) + b²(x + 1) = 0
⇒ (x + 1) (a2x + b2) = 0.
⇒ (x + 1) = 0, then x = -1
or
a2x + b2 = 0, then a2x = - b2.
⇒ x = `(-b^2)/a^2`
Hence x = -1, `(-b^2)/a^2`.
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