Question

Solve the following equation by factorization:

Зa²x² + 8abx + 4b² = 0, a ≠ 0

Answer 1

Given,

⇒ 3a²x² + 8abx + 4b² = 0

⇒ 3a²x² + 6abx + 2abx + 4b² = 0

⇒ 3ax(ax + 2b) + 2b(ax + 2b) = 0

⇒ (3ax + 2b)(ax + 2b) = 0

⇒ (3ax + 2b) = 0 or (ax + 2b) = 0   ...[Using zero-product rule]

⇒ 3ax = –2b or ax = –2b

⇒ `x = - (2b)/(3a)` or `x = - (2b)/a`

Hence, `x = {- (2b)/a, - (2b)/(3a)}`.