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प्रश्न
Solve the following equation by factorisation method:
`sqrt(x(x-7)) = 3sqrt2`
योग
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उत्तर
Given:
`sqrt(x(x-7)) = 3sqrt2`
`x(x-7) = (3sqrt2)^2`
x(x − 7) = 18
x2 − 7x − 18 = 0
Two numbers whose product = −18 and sum = −7.
These numbers are −9 and 2.
(x − 9) (x + 2) = 0
x − 9 = 0
⇒ x = 9
x + 2 = 0
⇒ x = −2
x = 9 or x = −2
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