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प्रश्न
Solve the following equation by factorisation method:
21x2 + 8x − 4 = 0
योग
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उत्तर
Given:
21x2 + 8x − 4 = 0
Find a × c
a = 21, b = 8, c = −4
a × c
= 21 × (−4)
= −84
Find two numbers whose product = −84 and sum = 8.
These numbers are:
14 and −6
21x2 + 14x − 6x − 4 = 0
(21x2 + 14x) + (−6x − 4) = 0
7x(3x + 2) −2(3x + 2) = 0
(3x + 2) (7x − 2) = 0
3x + 2 = 0
⇒ x = −`2/3`
7x − 2 = 0
⇒ x = `2/7`
`x = -2/3 or x = 2/7`
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