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प्रश्न
Solve the following equation by factorisation method:
`1/x + ((x-1))/2 = x, x\cancel=0`
योग
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उत्तर
Given:
`1/x + ((x-1))/2 = x, x\cancel=0`
Take LCM of denominators = 2x
Multiply the whole equation by 2x:
2 + x(x − 1) = 2x2
2 + x2 − x = 2x2
0 = 2x2 − x2 + x − 2
x2 + x − 2 = 0
Two numbers whose product = −2 and sum = 1:
2 and −1
(x + 2) (x − 1) = 0
x + 2 = 0
⇒ x = −2
x − 1 = 0
⇒ x = 1
x = −2 or x = 1
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