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प्रश्न
Solve the following equation and check your result:
`2y + 5/3 = 26/3 - y`
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उत्तर
`2y + 5/3 = 26/3 - y`
Transposing -y to L.H.S, we get
`2y + 5/3 + y = 26/3`
`3y + 5/3 = 26/3`
Now, transposing `5/3` to R.H.S, we get
`3y = 26/3 - 5/3`
`3y = 21/3`
Now, dividing both sides by 3, we get
`(3y)/3 = 21/3 xx 1/3`
`y = 21/9 = 7/3`
L.H.S = `2y + 5/3`
` = 2 xx 7/3 + 5/3`
` = 14/3 + 5/3`
` = 19/3`
R.H.S = `26/3 - y`
` = 26/3 - 7/3 `
`= 19/3`
L.H.S. = R.H.S.
Hence, the result obtained above is correct.
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