Advertisements
Advertisements
प्रश्न
Solve the following equation and check your result:
`2y + 5/3 = 26/3 - y`
Advertisements
उत्तर
`2y + 5/3 = 26/3 - y`
Transposing -y to L.H.S, we get
`2y + 5/3 + y = 26/3`
`3y + 5/3 = 26/3`
Now, transposing `5/3` to R.H.S, we get
`3y = 26/3 - 5/3`
`3y = 21/3`
Now, dividing both sides by 3, we get
`(3y)/3 = 21/3 xx 1/3`
`y = 21/9 = 7/3`
L.H.S = `2y + 5/3`
` = 2 xx 7/3 + 5/3`
` = 14/3 + 5/3`
` = 19/3`
R.H.S = `26/3 - y`
` = 26/3 - 7/3 `
`= 19/3`
L.H.S. = R.H.S.
Hence, the result obtained above is correct.
APPEARS IN
संबंधित प्रश्न
The perimeter of a rectangular swimming pool is 154 m. Its length is 2 m more than twice its breadth. What are the length and the breadth of the pool?
The base of an isosceles triangle is `4/3` cm. The perimeter of the triangle is `4 2/15` cm. What is the length of either of the remaining equal sides?
Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.
Solve the following equation and check your result:
`3m = 5m - 8/5`
Solve the following:
`(0.2x + 5)/(3.5x - 3) = 2/5`
Solve the following:
10x – 5 – 7x = 5x + 15 – 8
Solve the following:
0.25(4x – 5) = 0.75x + 8
Solve the following:
`(5x + 1)/(2x) = - 1/3`
Solve the following:
`(3t - 2)/3 + (2t + 3)/2 = t + 7/6`
If `1/2` is subtracted from a number and the difference is multiplied by 4, the result is 5. What is the number?
