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Solve the following differential equation: (ydx-xdy)cot(xy) = ny2 dx

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प्रश्न

Solve the following differential equation:

`(ydx - xdy) cot (x/y)` = ny2 dx

योग
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उत्तर

`(ydx - xdy) cot (x/y)` = ny2 dx

Dividing throughout by 'y2'

`((ydx - xdy)/y^2) cot (x/y)` = n dx

`"d"(x/y)* cot(x/y)` = n dx

`int cot(x/y)* "d"(x/y) = "n" int  "d"x`

`log sin(x/y)` = nx + c

`sin(x/y) = "e"^("n"x  +  "c")`

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Solution of First Order and First Degree Differential Equations
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 10: Ordinary Differential Equations - Exercise 10.5 [पृष्ठ १६२]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 10 Ordinary Differential Equations
Exercise 10.5 | Q 4. (vi) | पृष्ठ १६२

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