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प्रश्न
Solve `("d"y)/("d"x) = xy + x + y + 1`
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उत्तर
`("d"y)/("d"x) = xy + x + y + 1`
`("d"y)/("d"x) = xy + y + x + 1`
= y(x + 1) + 1(x + 1)
`("d"y)/("d"x) = (x + 1)(y + 1)`
`("d"y)/(y + 1) = (x + ) "d"x`
Integrating on both sides
`int ("d"y)/((y + 1)) = int (x + 1) "d"x`
`log|y + 1| = x^2/2 + x + "c"`
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