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प्रश्न
Solve the following:
0.4(3x – 1) = 0.5x + 1
योग
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उत्तर
Given, 0.4(3x – 1) = 0.5x + 1
⇒ 1.2x – 0.4 = 0.5x + 1
⇒ 1.2x – 0.5x = 1 + 0.4 ...[Transposing 0.5x to LHS and – 0.4 to RHS]
⇒ 0.7x = 1.4
⇒ `(0.7x)/0.7 = 1.4/0.7` ...[Dividing both sides by 0.7]
∴ x = 2
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