Solve for X: Log (X + 5) = 1

Solve for x: log (x + 5) = 1

योग

log (x + 5) = 1
= log 10
⇒ x + 5 = 10
⇒ x
= 10 - 5
= 5.

shaalaa.com

More About Logarithm

क्या इस प्रश्न या उत्तर में कोई त्रुटि है?

अध्याय 7: Logarithms - Exercise 10.2

अध्याय 7 Logarithms
Exercise 10.2 | Q 8.1

Evaluate :`1/( log_a bc + 1) + 1/(log_b ca + 1) + 1/ ( log_c ab + 1 )`

If log_√27x = 2 `(2)/(3)` , find x.

If m = log 20 and n = log 25, find the value of x, so that :
2 log (x - 4) = 2 m - n.

If log₂(x + y) = log₃(x - y) = `log 25/log 0.2`, find the values of x and y.

Solve for x: `("log"289)/("log"17)` = logx

Express log₁₀3 + 1 in terms of log₁₀x.

If 2 log x + 1 = log 360, find: log (3 x² - 8)

Express the following in a form free from logarithm:
`2"log" x + 1/2"log" y` = 1

If a b + b log a - 1 = 0, then prove that b^a.a^b = 10

Prove that: `(1)/("log"_2 30) + (1)/("log"_3 30) + (1)/("log"_5 30)` = 1