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प्रश्न
Solve for x and y:
`x/2 - y/9 = 6, x/7 + y/3 = 5`
योग
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उत्तर
Given: `x/2 - y/9 = 6, x/7 + y/3 = 5`
Step-wise calculation:
1. Clear denominators:
Multiply the first equation by 18:
`18 xx (x/2) - 18 xx (y/9) = 18 xx 6`
⇒ 9x – 2y = 108
Multiply the second equation by 21:
`21 xx (x/7) + 21 xx (y/3) = 21 xx 5`
⇒ 3x + 7y = 105
2. Eliminate x:
Multiply 3x + 7y = 105 by 3
⇒ 9x + 21y = 315
Subtract 9x – 2y = 108 from 9x + 21y = 315:
(9x + 21y) – (9x – 2y) = 315 – 108
⇒ 23y = 207
⇒ `y = 207/23`
⇒ y = 9
3. Substitute y = 9 into 3x + 7y = 105:
3x + 7(9) = 105
⇒ 3x + 63 = 105
⇒ 3x = 42
⇒ x = 14
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