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प्रश्न
Solve for x and y:
`5/x - 3/y = 1, 3/(2x )+ 2/(3y) = 5 (x ≠ 0, y ≠ 0)`
योग
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उत्तर
The given equations are:
`5/x - 3/y = 1` ...(i)
`3/(2x) + 2/(3y) = 5` ...(ii)
Putting` 1/x = u` and `1/y = v`, we get:
5u – 3v = 1 ...(iii)
⇒ `3/2 u + 2/3 v = 5`
⇒ `(9u + 4v)/6 = 5`
⇒ 9u + 4v = 30 ...(iv)
On multiplying (iii) by 4 and (iv) by 3, we get:
20u – 12v = 4 ...(v)
27u + 12v = 90 ...(vi)
On adding (iv) and (v), we get:
47u = 94 ⇒ u = 2
⇒ `1/x = 2 ⇒ x = 1/2`
On substituting `x = 1/2` in (i), we get:
`5/(1/2) - 3/y = 1`
⇒ `10 - 3/y = 1`
⇒ `3/y = (10 - 1)`
⇒ `3/y = 9`
`y = 3/9`
`y = 1/3`
Hence, the required solution is `x = 1/2` and `y = 1/3`.
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