Question

Solve for x and y:

2x + 3y = 0, 3x + 4y = 5

Answer 1

The given system of equation is:

2x + 3y = 0   ...(i)

3x + 4y = 5   ...(ii)

On multiplying (i) by 4 and (ii) by 3, we get:

8x + 12y = 0   ...(iii)

9x + 12y = 15   ...(iv)

On subtracting (iii) from (iv) we get:

x = 15

On substituting the value of x = 15 in (i), we get:

30 + 3y = 0

⇒ 3y = –30

⇒ y = –10

Hence, the solution is x = 15 and y = –10.