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प्रश्न
Solve for x and y:
`[(-2, 0),(3, 1)][(-1),(2x)] + 3[(-2),(1)] = 2[(y),(3)]`
योग
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उत्तर
`[(-2, 0),(3, 1)][(-1), (2x)] + 3[(-2),(1)] = 2[(y),(3)]`
`=> [(-2 xx -1 + 0 xx 2x),(3x - 1 + 1 xx 2x)] + [(-6),(3)] = [(2y),(6)]`
`=> [(2),(-3 + 2x)] + [(-6),(3)] = [(2y),(6)]`
`=> [(2 - 6),(-3 + 2x + 3)] = [(2y),(6)]`
`=> [(-4),(2x)] = [(2y),(6)]`
`=>` 2y = –4 and 2x = 6
y = –2 and x = 3
Thus, the values of x and y are 3, –2.
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