Advertisements
Advertisements
प्रश्न
Solve for x:
`(81)^(3/4) - (1/32)^(-2/5) + x(1/2)^(-1).2^0 = 27`
Advertisements
उत्तर
`(81)^(3/4) - (1/32)^(-2/5) + x(1/2)^(-1).2^0 = 27`
⇒ `3^(4 xx 3/4) - (2^- 5)^(-2/5) + x(2) = 27`
⇒ `3^3 - 2^2 + 2x = 27`
⇒ 2x + 27 − 4 = 27
⇒ 2x = 4
⇒ x = 2
APPEARS IN
संबंधित प्रश्न
Solve for x:
`2^(3x + 3) = 2^(3x + 1) + 48`
If m ≠ n and (m + n)-1 (m-1 + n-1) = mxny, show that : x + y + 2 = 0
Solve : 3x-1× 52y-3 = 225.
Evaluate : `4/(216)^(-2/3) + 1/(256)^(-3/4) + 2/(243)^(-1/5)`
Solve for x:
22x + 2x +2 - 4 x 23 = 0
Solve for x:
9 x 81x = `(1)/(27^(x - 3)`
If a = `2^(1/3) - 2^((-1)/3)`, prove that 2a3 + 6a = 3
If 2400 = 2x x 3y x 5z, find the numerical value of x, y, z. Find the value of 2-x x 3y x 5z as fraction.
Prove the following:
`(x^("a"+"b")/x^"c")^("a"-"b") · (x^("c"+"a")/(x^"b"))^("c"-"a") · ((x^("b"+"c"))/(x"a"))^("b"-"c")` = 1
Prove the following:
`root("ab")(x^"a"/x^"b")·root("bc")(x^"b"/x^"c")·root("ca")(x^"c"/x^"a")` = 1
