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Solve the Following Quadratic Equations by Factorization: `(X-a)/(X-b)+(X-b)/(X-a)=A/B+B/A`

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प्रश्न

Solve the following quadratic equations by factorization:

`(x-a)/(x-b)+(x-b)/(x-a)=a/b+b/a`

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उत्तर

We have been given

`(x-a)/(x-b)+(x-b)/(x-a)=a/b+b/a`

`(x^2+a^2-2ax+x^2+b^2-2bx)/(x^2-(a+b)x+ab)=(a^2+b^2)/(ab)`

2abx2 - 2(ab)(a + b)x + ab(a2 + b2) = (a2 + b2)x2 - (a + b)(a2 + b2)x + ab(a2 + b2)

(a - b)2x2 - (a + b)(a - b)2x = 0

x(a - b)2(x - (a + b)) = 0

Therefore,

x(a - b)2 = 0

x = 0

or,

x - (a + b) = 0

x = a + b

Hence, x = 0 or x = a + b.

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अध्याय 4: Quadratic Equations - Exercise 4.3 [पृष्ठ २०]

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आर.डी. शर्मा Mathematics [English] Class 10
अध्याय 4 Quadratic Equations
Exercise 4.3 | Q 45 | पृष्ठ २०

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