Advertisements
Advertisements
प्रश्न
Solve the following quadratic equation for x: x2 – 2ax – (4b2 – a2) = 0
Advertisements
उत्तर
x2 – 2ax – (4b2 – a2) = 0
⇒ x2 + (2b – a)x – (2b + a)x – (4b2 – a2) = 0
⇒ x(x + 2b – a) – (2b + a)(x + 2b – a) = 0
⇒ (x + 2b – a)(x – 2b – a) = 0
⇒ (x + 2b – a) = 0, (x – 2b – a) = 0
∴ x = a − 2b, a + 2b
APPEARS IN
संबंधित प्रश्न
Some students planned a picnic. The budget for food was Rs. 500. But, 5 of them failed to go and thus the cost of food for each member increased by Rs. 5. How many students attended the picnic?
Solve the following quadratic equation by factorisation.
3x2 - 2√6x + 2 = 0
Solve the following equation: 4x2 + 16x = 0
The sum of the ages of a father and his son is 45 years. Five years ago, the product of their ages was 124. Determine their present ages.
Solve the following equation and give your answer up to two decimal places:
x2 − 5x − 10 = 0
Solve the following equation by factorization
x(6x – 1) = 35
Solve the following equation by factorization
`x^2 - (1 + sqrt(2))x + sqrt(2)` = 0
Solve the following equation by factorization
`(x + 2)/(x + 3) = (2x - 3)/(3x - 7)`
The hotel bill for a number of people for an overnight stay is Rs. 4800. If there were 4 more, the bill each person had to pay would have reduced by Rs. 200. Find the number of people staying overnight.
The product of two successive integral multiples of 5 is 300. Then the numbers are:
