Advertisements
Advertisements
प्रश्न
Solve the following quadratic equation for x: x2 – 2ax – (4b2 – a2) = 0
Advertisements
उत्तर
x2 – 2ax – (4b2 – a2) = 0
⇒ x2 + (2b – a)x – (2b + a)x – (4b2 – a2) = 0
⇒ x(x + 2b – a) – (2b + a)(x + 2b – a) = 0
⇒ (x + 2b – a)(x – 2b – a) = 0
⇒ (x + 2b – a) = 0, (x – 2b – a) = 0
∴ x = a − 2b, a + 2b
APPEARS IN
संबंधित प्रश्न
Find the two consecutive natural numbers whose product is 20.
The area of a right angled triangle is 165 m2. Determine its base and altitude if the latter exceeds the former by 7 m.
Solve the following equation: 4x2 - 13x - 12 = 0
Solve the following equation: `(2"x")/("x" - 4) + (2"x" - 5)/("x" - 3) = 25/3`
Three consecutive natural numbers are such that the square of the first increased by the product of other two gives 154. Find the numbers.
If `sqrt (2/3)` is a solution of equation 3x2 + mx + 2 = 0, find the value of m.
A car covers a distance of 400 km at a certain speed. Had the speed been 12 km/hr more, the time taken for the journey would have been 1 hour 40 minutes less. Find the original speed of the car.
Solve the following equation by factorization
`(1)/(x - 3) - (1)/(x + 5) = (1)/(6)`
The sum of two numbers is 9 and the sum of their squares is 41. Taking one number as x, form ail equation in x and solve it to find the numbers.
Find three consecutive odd integers, the sum of whose squares is 83.
