Advertisements
Advertisements
प्रश्न
Solve the following quadratic equation using formula method only
15x2 - 28 = x
Advertisements
उत्तर
15x2 - 28 = x
15x2 - x - 28 = x
a = 15 ; b = -1 ; c = -28
D = b2 - 4ac
= (-1)2 - 4(15)(-28)
= 1 + 1680
= 1681
x = `(- "b" ± sqrt ("b"^2 - 4 "ac"))/(2a)`
x = `(1 +- sqrt 1681)/30`
x = `(1 + 41)/30` , x = `(1 - 41)/30`
x = `42/30` , x = `-40/30`
x = `7/5` , x = `-4/3`
APPEARS IN
संबंधित प्रश्न
Find the value of k for which the following equation has equal roots.
x2 + 4kx + (k2 – k + 2) = 0
Determine the nature of the roots of the following quadratic equation:
2(a2 + b2)x2 + 2(a + b)x + 1 = 0
For what values of k, the roots of the equation x2 + 4x +k = 0 are real?
Determine, if 3 is a root of the given equation
`sqrt(x^2 - 4x + 3) + sqrt(x^2 - 9) = sqrt(4x^2 - 14x + 16)`.
In each of the following, determine whether the given numbers are roots of the given equations or not; x2 – x + 1 = 0; 1, – 1
If a is a root of the equation x2 – (a + b)x + k = 0, find the value of k.
The sum of the roots of the quadratic equation 3x2 – 9x + 5 = 0 is:
If the roots of px2 + qx + 2 = 0 are reciprocal of each other, then:
Find the roots of the quadratic equation by using the quadratic formula in the following:
`x^2 - 3sqrt(5)x + 10 = 0`
One root of equation 3x2 – mx + 4 = 0 is 1, the value of m is ______.
