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प्रश्न
Solve the following equation and verify your answer:
\[\frac{2 - y}{y + 7} = \frac{3}{5}\]
योग
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उत्तर
\[\frac{2 - y}{y + 7} = \frac{3}{5}\]
\[\text{ or }10 - 5y = 3y + 21 (\text{ After cross multiplication })\]
\[\text{ or }3y + 5y = 10 - 21\]
\[\text{ or }8y = - 11\]
\[\text{ or }y = \frac{- 11}{8}\]
\[ \therefore y = \frac{- 11}{8}\text{ is the solution of the given equation . }\]
\[\text{ Check: }\]
\[\text{ Substituting }y = \frac{- 11}{8}\text{ in the given equation, we get: }\]
\[\text{ L . H . S . }= \frac{2 - \frac{- 11}{8}}{\frac{- 11}{8} + 7} = \frac{16 + 11}{- 11 + 56} = \frac{27}{45} = \frac{3}{5}\]
\[\text{ R . H . S . }= \frac{3}{5}\]
\[ \therefore\text{ L . H . S . = R . H . S . for }y = \frac{- 11}{8}\]
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