हिंदी

Solid ammonium dichromate decomposes as: (NHA4)A2CrA2OA7⟶NA2+CrA2OA3+4HA2O If 63 g of ammonium dichromate decomposes. Calculate the quantity in moles of (NH4)2Cr2O7.

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प्रश्न

Solid ammonium dichromate decomposes as:

\[\ce{(NH4)2Cr2O7 -> N2 + Cr2O3 + 4H2O}\]

If 63 g of ammonium dichromate decomposes. Calculate the quantity in moles of (NH4)2Cr2O7.

संख्यात्मक
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उत्तर

Molecular mass of ammonium dichromate = 2(14 + 4) + 104 + 112

= 252 g

Number of moles = `"Weight"/"Molecular weight"`

= `63/252`

= 0.25 moles

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अध्याय 5: Mole concept and Stoichiometry - MISCELLANEOUS EXERCISE [पृष्ठ ९६]

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एस पी सिंग Concise Chemistry [English] Class 10 ICSE
अध्याय 5 Mole concept and Stoichiometry
MISCELLANEOUS EXERCISE | Q 24. (a) | पृष्ठ ९६
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