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∫ Sin 3 X − Cos 3 X Sin 2 X Cos 2 X D X - Mathematics

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प्रश्न

\[\int\frac{\sin^3 x - \cos^3 x}{\sin^2 x \cos^2 x} dx\]
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उत्तर

\[\int\left( \frac{\sin^3 x - \cos^3 x}{\sin^2 x \cdot \cos^2 x} \right)dx\]
\[ = \int\frac{\sin^3 x}{\sin^2 x \cdot \cos^2 x}dx - \int\frac{\cos^3 x}{\sin^2 x \cdot \cos^2 x}dx\]
\[ = \int\frac{\sin x}{\cos^2 x}dx - \int\frac{\cos x}{\sin^2 x}dx\]
\[ = \int\frac{\sin x}{\cos x} \times \frac{1}{\cos x}dx - \int\frac{\cos x}{\sin x} \times \frac{1}{\sin x}dx\]
`=∫ sec x  tan x  dx - ∫  "cosec"  x  cot x  dx`
\[ = \sec x - \left( - \text{cosec  x} \right) + C\]
\[ = \sec x + \text{cosec x }+ C\]

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अध्याय 19: Indefinite Integrals - Exercise 19.02 [पृष्ठ १५]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 19 Indefinite Integrals
Exercise 19.02 | Q 23 | पृष्ठ १५

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