Advertisements
Advertisements
प्रश्न
Simplify the following using the identities: \[\frac{8 . 63 \times 8 . 63 - 1 . 37 \times 1 . 37}{0 . 726}\]
Advertisements
उत्तर
Let us consider the following expression: \[\frac{8 . 63 \times 8 . 63 - 1 . 37 \times 1 . 37}{0 . 726} = \frac{8 . {63}^2 - 1 . {37}^2}{0 . 726}\]
Using the identity \[\left( a + b \right)\left( a - b \right) = a^2 - b^2\] we get:
\[\frac{8 . 63 \times 8 . 63 - 1 . 37 \times 1 . 37}{0 . 726} = \frac{8 . {63}^2 - 1 . {37}^2}{0 . 726} = \frac{\left( 8 . 63 + 1 . 37 \right)\left( 8 . 63 - 1 . 37 \right)}{0 . 726}\]
\[\Rightarrow \frac{8 . 63 \times 8 . 63 - 1 . 37 \times 1 . 37}{0 . 726} = \frac{\left( 8 . 63 + 1 . 37 \right)\left( 8 . 63 - 1 . 37 \right)}{0 . 726}\]
\[ \Rightarrow \frac{8 . 63 \times 8 . 63 - 1 . 37 \times 1 . 37}{0 . 726} = \frac{\left( 8 . 63 + 1 . 37 \right)\left( 8 . 63 - 1 . 37 \right)}{0 . 726}\]
\[ \Rightarrow \frac{8 . 63 \times 8 . 63 - 1 . 37 \times 1 . 37}{0 . 726} = \frac{10 \times 7 . 26}{0 . 726}\]
\[ \Rightarrow \frac{8 . 63 \times 8 . 63 - 1 . 37 \times 1 . 37}{0 . 726} = \frac{10 \times {7 . 26}^{10}}{0 . 726}\]
\[ \Rightarrow \frac{8 . 63 \times 8 . 63 - 1 . 37 \times 1 . 37}{0 . 726} = 100\]
Thus, the answer is 100.
APPEARS IN
संबंधित प्रश्न
Show that `(4pq + 3q)^2 - (4pq - 3q)^2 = 48pq^2`
Show that (a - b)(a + b) + (b - c) (b + c) + (c - a) (c + a) = 0
Simplify the following using the formula: (a − b)(a + b) = a2 − b2: (467)2 − (33)2
Simplify the following using the formula: (a − b)(a + b) = a2 − b2: (79)2 − (69)2
Find the following product: (3x + 5) (3x + 11)
Evaluate the following: 53 × 55
Simplify:
(ab – c)2 + 2abc
Simplify:
(s2t + tq2)2 – (2stq)2
Expand the following, using suitable identities.
(x2y – xy2)2
Using suitable identities, evaluate the following.
(103)2
