Advertisements
Advertisements
प्रश्न
Simplify:
\[\left\{ 3^{- 1} \times 4^{- 1} \right\}^{- 1} \times 5^{- 1}\]
योग
Advertisements
उत्तर
\[\left\{ 3^{- 1} \times 4^{- 1} \right\}^{- 1} \times 5^{- 1}\]`-(1/3xx1/4)^(-1)xx1/5` → (a−1 = 1/a)
\[= \left( \frac{1}{12} \right)^{- 1} \times \frac{1}{5}\]
\[= 12 \times \frac{1}{5}\] → (a−1 = 1/a)
\[= \frac{12}{5}\]
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Find the value of the following:
\[\left( \frac{1}{2} \right)^{- 2} + \left( \frac{1}{3} \right)^{- 2} + \left( \frac{1}{4} \right)^{- 2}\]
Write the following in exponential form:
\[\left( \frac{2}{5} \right)^{- 2} \times \left( \frac{2}{5} \right)^{- 2} \times \left( \frac{2}{5} \right)^{- 2}\]
Evaluate:
5−2
By what number should 5−1 be multiplied so that the product may be equal to (−7)−1?
Find x, if \[\left( \frac{1}{4} \right)^{- 4} \times \left( \frac{1}{4} \right)^{- 8} = \left( \frac{1}{4} \right)^{- 4x}\]
Cube of \[\frac{- 1}{2}\] is
\[\left( \frac{- 1}{2} \right)^5 \times \left( \frac{- 1}{2} \right)^3\] is equal to
\[\left( \frac{2}{3} \right)^{- 5} \times \left( \frac{5}{7} \right)^{- 5}\] is equal to
Evaluate.
`(8^(-1)xx5^(3))/2^(-4)`
Simplify and express the result in power notation with positive exponent.
(3−7 ÷ 3−10) × 3−5
