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प्रश्न
Simplify `1/(("n" - 1)!) + (1 - "n")/(("n" + 1)!)`
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उत्तर
`1/(("n" - 1)!) + (1 - "n")/(("n" + 1)!)`
= `1/(("n" - 1)!) + (1 - "n")/(("n" + 1)"n"("n" - 1)!)`
= `1/(("n" - 1)!)[1 + (1 - "n")/("n"("n" + 1))]`
= `1/(("n" - 1)!)[("n"("n" + 1) + (1 - "n"))/("n"("n" + 1))]`
= `1/(("n" - 1)!)[("n"^2 + "n" + 1 - "n")/("n"("n" + 1))]`
= `("n"^2 + 1)/("n"("n" - 1)!("n" + 1))`
= `("n"^2 + 1)/("n"! xx ("n" + 1))`
= `("n"^2 + 1)/(("n" + 1)!)`
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