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प्रश्न
Show that the system of equations
2x – 3y = 5, 6x – 9y = 15
has an infinite number of solutions.
योग
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उत्तर
The given system of equations:
2x – 3y = 5
⇒ 2x – 3y – 5 = 0 ...(i)
6x – 9y = 15
⇒ 6x – 9y – 15 = 0 ...(ii)
These equations are of the following forms:
a1x + b1y + c1 = 0, a2x + b2y + c2 = 0
Here, a1 = 2, b1 = –3, c1 = –5 and a2 = 6, b2 = –9, c2 = –15
∴ `(a_1)/(a_2) = 2/6 = 1/3,(b_1)/(b_2) = (−3)/(−9) = 1/3` and `(c_1)/(c_2 )= (−5)/(−15) = 1/3`
Thus, `(a_1)/(a_2) = (b_1)/(b_2) = (c_1)/(c_2)`
Hence, the given system of equations has an infinite number of solutions.
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