हिंदी

Show that the system of equations 2x – 3y = 5, 6x – 9y = 15 has an infinite number of solutions.

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प्रश्न

Show that the system of equations

2x – 3y = 5, 6x – 9y = 15

has an infinite number of solutions.

योग
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उत्तर

The given system of equations:

2x – 3y = 5

⇒ 2x – 3y – 5 = 0   ...(i)

6x – 9y = 15

⇒ 6x – 9y – 15 = 0   ...(ii)

These equations are of the following forms:

a1x + b1y + c1 = 0, a2x + b2y + c2 = 0

Here, a1 = 2, b1 = –3, c1 = –5 and a2 = 6, b2 = –9, c2 = –15

∴ `(a_1)/(a_2) = 2/6 = 1/3,(b_1)/(b_2) = (−3)/(−9) = 1/3` and `(c_1)/(c_2 )= (−5)/(−15) = 1/3`

Thus, `(a_1)/(a_2) = (b_1)/(b_2) = (c_1)/(c_2)`

Hence, the given system of equations has an infinite number of solutions.

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अध्याय 3: Linear Equations in Two Variables - EXERCISE 3D [पृष्ठ १२९]

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 3 Linear Equations in Two Variables
EXERCISE 3D | Q 10. | पृष्ठ १२९
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