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प्रश्न
Show that the progression 11, 13, 15, 17, 19, ......... is an A.P. Write down its (i) first term (ii) common difference (iii) 20th term.
योग
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उत्तर
Common difference is constant:
$$13 - 11 = 15 - 13 = 17 - 15 = 19 - 17 = 2$$.
Hence it is an A.P.
First term $$a = 11$$, common difference $$d = 2$$.
20th term: $$T_{20} = a + (20 - 1)d$$
$$= 11 + 19\times 2$$
$$= 49$$
So first term = 11, common difference = 2, 20th term = 49.
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