Question

Show that the points A(- 2, 5), B(2, – 3) and C(0, 1) are collinear.

Answer 1

m₁ = Slope ofAB
= `(-3 - 5)/(2 - (-2)) = (8)/(4)` = -2
m₂ = slop of BC
= `(1 - (-3))/(0 - 2) = (4)/(-2)` = -2
Hence m₁ = m₂ = -2
So, AB is parallel to BC.
But B is common to AB and BC.
Hence, A, B and C must lies on the same line.
Hence proved.