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F ( X ) = { X − | X | 2 , W H E N X ≠ 0 2 , W H E N X = 0 is Discontinuous at X = 0. - Mathematics

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प्रश्न

Show that

\[f\left( x \right)\] = \begin{cases}\frac{x - \left| x \right|}{2}, when & x \neq 0 \\ 2 , when & x = 0\end{cases}

is discontinuous at x = 0.

 
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उत्तर

The given function can be rewritten as:

\[f\left( x \right) = \begin{cases}\frac{x - x}{2}, when x > 0 \\ \frac{x + x}{2}, when x < 0 \\ 2, when x = 0\end{cases}\]
\[\Rightarrow\]
\[f\left( x \right) = \begin{cases}0, when x > 0 \\ x, when x < 0 \\ 2, when x = 0\end{cases}\]
We observe
(LHL at x = 0) = \[\lim_{x \to 0^-} f\left( x \right) = \lim_{h \to 0} f\left( 0 - h \right) = \lim_{h \to 0} f\left( - h \right)\]
\[= \lim_{h \to 0} \left( - h \right) = 0\]
(RHL at x = 0) = 
\[\lim_{x \to 0^+} f\left( x \right) = \lim_{h \to 0} f\left( 0 - h \right) = \lim_{h \to 0} f\left( h \right)\]
\[\lim_{h \to 0} 0 = 0\]
And, 
\[f\left( 0 \right) = 2\]
\[\lim_{x \to 0^-} f\left( x \right) = \lim_{x \to 0^+} f\left( x \right) \neq f\left( 0 \right)\]

Thus, f(x) is discontinuous at x = 0.

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अध्याय 9: Continuity - Exercise 9.1 [पृष्ठ १७]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 9 Continuity
Exercise 9.1 | Q 8 | पृष्ठ १७

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