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Select the correct answer from the given alternatives: If f(x) = (sin2x)tan5x(e2x-1)2, for x ≠ 0 is continuous at x = 0, then f(0) is

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प्रश्न

Select the correct answer from the given alternatives:

If f(x) = `((sin2x)tan5x)/("e"^(2x) - 1)^2`, for x ≠ 0 is continuous at x = 0, then f(0) is

विकल्प

  • `10/"e"^2`

  • `10/"e"^4`

  • `5/4`

  • `5/2`

MCQ
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उत्तर

`5/2`

Explanation;

f(x) is continuous at x = 0

f(0) = `lim_(x -> 0) "f"(x)`

= `lim_(x -> 0) ((sin2x)(tan5x))/("e"^(2x) - 1)^2`

= `(lim_(x -> 0)(sin2x)/(2x) xx lim_(x -> 0) (tan5x)/(5x) xx 2 xx 5)/((lim_(x -> 0) ("e"^(2x) - 1)/(2x)) xx (2)^2`

= `(1 xx 1 xx 2 xx 5)/((1)^2 xx 4)  ...[(because x -> 0","  2x -> 0","  5x -> 0),("and" lim_(theta -> 0) sintheta/theta = 1"," lim_(theta -> 0) tantheta/theta = 1)]`

= `5/2`

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अध्याय 8: Continuity - MISCELLANEOUS EXERCISE-8 [पृष्ठ १७६]

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बालभारती Mathematics and Statistics (Arts and Science) Part 2 [English] Standard 11 Maharashtra State Board
अध्याय 8 Continuity
MISCELLANEOUS EXERCISE-8 | Q (I) (3) | पृष्ठ १७६

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