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Select the Appropriate Alternative. (1) in ∆Abc and ∆Pqr, in a One to One Correspondence - Geometry Mathematics 2

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प्रश्न

Select the appropriate alternative.
In ∆ABC and ∆PQR, in a one to one correspondence \[\frac{AB}{QR} = \frac{BC}{PR} = \frac{CA}{PQ}\] 

विकल्प

  • ∆PQR ~ ∆ABC 

  • ∆PQR ~ ∆CAB 

  • ∆CBA ~ ∆PQR 

  • ∆BCA ~ ∆PQR

MCQ
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उत्तर

\[\frac{AB}{QR} = \frac{BC}{PR} = \frac{CA}{PQ}\] 

By SSS test of similarity
 ∆PQR ~ ∆CAB
Hence, the correct option is ∆PQR ~ ∆CAB.

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अध्याय 1: Similarity - Problem Set 1 [पृष्ठ २६]

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बालभारती Mathematics 2 [English] Standard 10 Maharashtra State Board
अध्याय 1 Similarity
Problem Set 1 | Q 1.1 | पृष्ठ २६
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