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Rationalise the denominator: (sqrt(5) + sqrt(2))/(sqrt(5) – sqrt(2)) - Mathematics

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प्रश्न

Rationalise the denominator:

`(sqrt(5) + sqrt(2))/(sqrt(5) - sqrt(2))`

योग
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उत्तर

To rationalize the denominator of the expression

`(sqrt(5) + sqrt(2))/(sqrt(5) - sqrt(2))`,

we need to multiply both the numerator and the denominator by the conjugate of the denominator, which is `sqrt(5) + sqrt(2)`.

`(sqrt(5) + sqrt(2))/(sqrt(5) - sqrt(2)) xx (sqrt(5) + sqrt(2))/(sqrt(5) + sqrt(2)) = (sqrt(5) + sqrt(2))^2/((sqrt(5))^2 - (sqrt(2))^2`

Step 1: Simplify the denominator

Use the identity (a – b)(a + b) = a2 – b2:

`(sqrt(5))^2 - (sqrt(2))^2`

= 5 – 2

= 3

Step 2: Expand the numerator

Now, expand `(sqrt(5) + sqrt(2))^2`:

`(sqrt(5) + sqrt(2))^2`

= `(sqrt(5))^2 + 2(sqrt(5))(sqrt(2)) + (sqrt(2))^2`

= `5 + 2sqrt(10) + 2`

= `7 + 2sqrt(10)`

Step 3: Put everything together

Thus, the expression becomes:

`(7 + 2sqrt(10))/3`

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अध्याय 1: Rational and Irrational Numbers - MISCELLANEOUS EXERCISE [पृष्ठ १७]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
अध्याय 1 Rational and Irrational Numbers
MISCELLANEOUS EXERCISE | Q 4. (iii) | पृष्ठ १७
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