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प्रश्न
Rationalise the denominator of `3/(4 - sqrt(7))`.
योग
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उत्तर
To rationalise the denominator of `3/(4 - sqrt(7))`
Multiply numerator and denominator by the conjugate of the denominator:
`3/(4 - sqrt(7)) xx (4 + sqrt(7))/(4 + sqrt(7)) = (3(4 + sqrt(7)))/((4 - sqrt(7))(4 + sqrt(7))`
Now compute:
Denominator: `(4 - sqrt(7))(4 + sqrt(7))`
= 16 – 7
= 9
Numerator: `3(4 + sqrt(7))`
= `12 + 3sqrt(7)`
So, `(12 + 3sqrt(7))/9`
Now simplify:
= `(3(4 + sqrt(7)))/9`
= `(4 + sqrt(7))/3`
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