Advertisements
Advertisements
प्रश्न
Prove the following identities:
`(cotA - cosecA)^2 = (1 - cosA)/(1 + cosA)`
Advertisements
उत्तर
`(cotA - cosecA)^2 = (1 - cosA)/(1 + cosA)`
`cot^2A - 2cotA cosecA + cosec^2x = (1 - cosA)/(1 + cosA)`
`(cos^2A)/(sin^2A) - (2cosA)/(sin^2A) + 1/(sin^2A) = (1 - cosA)/(1 + cosA)`
`(cos^2A - 2cosA + 1)/(sin^2A) = (1 - cosA)/(1 + cosA)`
`(cos^2A - 2cosA + 1)/(1 - cos^2A) = (1 - cosA)/(1 + cosA)`
`((1 - cosA)(1 - cosA))/((1 + cosA)(1 - cosA)) = (1 - cosA)/(1 + cosA)`
`(1 - cosA)/(1 + cosA) = (1 - cosA)/(1 + cosA)`
संबंधित प्रश्न
Prove the following identities:
`1/(1 + cosA) + 1/(1 - cosA) = 2cosec^2A`
What is the value of \[\frac{\tan^2 \theta - \sec^2 \theta}{\cot^2 \theta - {cosec}^2 \theta}\]
(sec A + tan A) (1 − sin A) = ______.
Prove the following identity :
`(1 - sin^2θ)sec^2θ = 1`
Prove the following identity :
`sinA/(1 + cosA) + (1 + cosA)/sinA = 2cosecA`
Prove the following identity :
`sin^8θ - cos^8θ = (sin^2θ - cos^2θ)(1 - 2sin^2θcos^2θ)`
If sin θ = `1/2`, then find the value of θ.
If 5x = sec θ and `5/x` = tan θ, then `x^2 - 1/x^2` is equal to
Prove that `(sin^2theta)/(cos theta) + cos theta` = sec θ
Prove that sin θ (1 – tan θ) – cos θ (1 – cot θ) = cosec θ – sec θ
