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Prove the following: ∫0π42tan3xdx=1-log2 - Mathematics

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प्रश्न

Prove the following:

`int_0^(pi/4) 2 tan^3 xdx = 1 - log 2`

योग
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उत्तर

`int_0^(pi/4) 2 tan^3 x dx`

`= int_0^(pi/4) 2 tan x* tan^2 x  dx`

`= int_0^(pi/4) 2 tan x (sec^2 x - 1)  dx`

`= 2 int_0^(pi/4) (tan x) sec^2 x dx - 2 int_0^(pi/2) tan x dx`

`= 2 [(tan^2 x)/2]_0^(pi/4) - 2 [- log |cos x|] _0^(pi/4)`

`= (tan^2  pi/4 - tan^2 0) + 2 (log cos  pi/4 - log cos 0)`

`= (1 - 0) + 2 (log  1/ sqrt2 - log 1)`

`= 1 + 2 (log 1 - log sqrt 2 - log 1)`

`= 1 + 2 xx (-1/2 log 2)`

= 1 - log 2

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अध्याय 7: Integrals - Exercise 7.12 [पृष्ठ ३५३]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 7 Integrals
Exercise 7.12 | Q 38 | पृष्ठ ३५३

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