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प्रश्न
Prove that EV = Δ = ∇E
आकृति
योग
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उत्तर
E∇ = EE–1Δ .......[∵ ∇ = E–1Δ]
= Δ .......(1)
∇E = E–1ΔE
= E–1EΔ
= Δ .......(2)
From (1) and (2)
E∇ = Δ = ∇E
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